(3x^2+9x^2+45x)/9x^2=0

Solution for (3x^2+9x^2+45x)/9x^2=0 equation:

(3x^2+9x^2+45x)/9x^2=0


Domain of the equation: 9x^2!=0

x^2!=0/9

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


(3x^2+9x^2+45x)=0

We get rid of parentheses

3x^2+9x^2+45x=0

We add all the numbers together, and all the variables

12x^2+45x=0

a = 12; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·12·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*12}=\frac{-90}{24}
=-3+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*12}=\frac{0}{24}
=0
$